Glen, Paul and Peter shared $245. During a shopping trip, Glen spent
27 of his share, Paul spent
35 of his share and Peter spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Glen and Paul have than Peter at first?
| |
Glen |
Paul |
Peter |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$245 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Glen, Paul and Peter spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 245
1 u = 245 ÷ 49 = 5
Amount that Glen and Paul have at first
= 21 u + 10 u
= 31 u
Amount that Glen and Paul have more than Peter at first
= 31 u - 18 u
= 13 u
= 13 x 5
= $65
Answer(s): $65
