Ian, Warren and Mark shared $258. During a shopping trip, Ian spent
38 of his share, Warren spent
25 of his share and Mark spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Ian and Warren have than Mark in the end?
| |
Ian |
Warren |
Mark |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
2x6 =
12 u |
$258 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Ian, Warren and Mark spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u
43 u = 258
1 u = 258 ÷ 43 = 6
Amount that Ian and Warren have in the end
= 10 u + 9 u
= 19 u
Amount that Ian and Warren have more than Mark in the end
= 19 u - 6 u
= 13 u
= 13 x 6
= $78
Answer(s): $78
