Jeremy, Carl and Pierre shared $325. During a shopping trip, Jeremy spent ³₁₀ of his share, Carl spent ²₇ of his share and Pierre spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Jeremy and Carl have than Pierre in the end?

	Jeremy	Carl	Pierre	Total
Before	10x2 = 20 u	7x3 = 21 u	4x6 = 24 u	$325
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	7x2 = 14 u	5x3 = 15 u	3x6 = 18 u

The amounts that Jeremy, Carl and Pierre spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 20 u + 21 u + 24 u
= 65 u

65 u = 325

1 u = 325 ÷ 65 = 5

Amount that Jeremy and Carl have in the end
= 14 u + 15 u
= 29 u

Amount that Jeremy and Carl have more than Pierre in the end
= 29 u - 18 u
= 11 u
= 11 x 5
= $55

Answer(s): $55