Luis, Jenson and Rael shared $261. During a shopping trip, Luis spent
34 of his share, Jenson spent
23 of his share and Rael spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Luis and Jenson have than Rael in the end?
| |
Luis |
Jenson |
Rael |
Total |
| Before |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
$261 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
1x2 =
2 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Luis, Jenson and Rael spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 8 u + 9 u + 12 u
= 29 u
29 u = 261
1 u = 261 ÷ 29 = 9
Amount that Luis and Jenson have in the end
= 2 u + 3 u
= 5 u
Amount that Luis and Jenson have more than Rael in the end
= 5 u - 6 u
= -1 u
= -1 x 9
= $-9
Answer(s): $-9
