Tim, Jack and Charlie shared $440. During a shopping trip, Tim spent
27 of his share, Jack spent
35 of his share and Charlie spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Tim and Jack have than Charlie in the end?
| |
Tim |
Jack |
Charlie |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
4x6 =
24 u |
$440 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
3x6 =
18 u |
|
The amounts that Tim, Jack and Charlie spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 24 u
= 55 u
55 u = 440
1 u = 440 ÷ 55 = 8
Amount that Tim and Jack have in the end
= 15 u + 4 u
= 19 u
Amount that Tim and Jack have more than Charlie in the end
= 19 u - 18 u
= 1 u
= 1 x 8
= $8
Answer(s): $8
