Sam, Sean and Archie shared $186. During a shopping trip, Sam spent
35 of his share, Sean spent
23 of his share and Archie spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Sam and Sean have than Archie at first?
| |
Sam |
Sean |
Archie |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$186 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Sam, Sean and Archie spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 186
1 u = 186 ÷ 31 = 6
Amount that Sam and Sean have at first
= 10 u + 9 u
= 19 u
Amount that Sam and Sean have more than Archie at first
= 19 u - 12 u
= 7 u
= 7 x 6
= $42
Answer(s): $42
