Neave, Gabriel and Owen shared $430. During a shopping trip, Neave spent ²₇ of his share, Gabriel spent ³₅ of his share and Owen spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Neave and Gabriel have than Owen in the end?

	Neave	Gabriel	Owen	Total
Before	7x3 = 21 u	5x2 = 10 u	2x6 = 12 u	$430
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	5x3 = 15 u	2x2 = 4 u	1x6 = 6 u

The amounts that Neave, Gabriel and Owen spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 21 u + 10 u + 12 u
= 43 u

43 u = 430

1 u = 430 ÷ 43 = 10

Amount that Neave and Gabriel have in the end
= 15 u + 4 u
= 19 u

Amount that Neave and Gabriel have more than Owen in the end
= 19 u - 6 u
= 13 u
= 13 x 10
= $130

Answer(s): $130