Henry, George and Rael shared $328. During a shopping trip, Henry spent
27 of his share, George spent
34 of his share and Rael spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Henry and George have than Rael at first?
| |
Henry |
George |
Rael |
Total |
| Before |
7x3 =
21 u |
4x2 =
8 u |
2x6 =
12 u |
$328 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Henry, George and Rael spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 8 u + 12 u
= 41 u
41 u = 328
1 u = 328 ÷ 41 = 8
Amount that Henry and George have at first
= 21 u + 8 u
= 29 u
Amount that Henry and George have more than Rael at first
= 29 u - 12 u
= 17 u
= 17 x 8
= $136
Answer(s): $136
