Daniel, Billy and Tim shared $235. During a shopping trip, Daniel spent
37 of his share, Billy spent
25 of his share and Tim spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Daniel and Billy have than Tim at first?
| |
Daniel |
Billy |
Tim |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
3x6 =
18 u |
$235 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that Daniel, Billy and Tim spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u
47 u = 235
1 u = 235 ÷ 47 = 5
Amount that Daniel and Billy have at first
= 14 u + 15 u
= 29 u
Amount that Daniel and Billy have more than Tim at first
= 29 u - 18 u
= 11 u
= 11 x 5
= $55
Answer(s): $55
