Jeremy, Jack and Oscar shared $70. During a shopping trip, Jeremy spent
25 of his share, Jack spent
34 of his share and Oscar spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Jeremy and Jack have than Oscar in the end?
| |
Jeremy |
Jack |
Oscar |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$70 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Jeremy, Jack and Oscar spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 70
1 u = 70 ÷ 35 = 2
Amount that Jeremy and Jack have in the end
= 9 u + 2 u
= 11 u
Amount that Jeremy and Jack have more than Oscar in the end
= 11 u - 6 u
= 5 u
= 5 x 2
= $10
Answer(s): $10
