Sean, Reggie and Will shared $583. During a shopping trip, Sean spent
37 of his share, Reggie spent
25 of his share and Will spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Sean and Reggie have than Will in the end?
| |
Sean |
Reggie |
Will |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$583 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Sean, Reggie and Will spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 583
1 u = 583 ÷ 53 = 11
Amount that Sean and Reggie have in the end
= 8 u + 9 u
= 17 u
Amount that Sean and Reggie have more than Will in the end
= 17 u - 18 u
= -1 u
= -1 x 11
= $-11
Answer(s): $-11
