Julian, Owen and George shared $328. During a shopping trip, Julian spent
37 of his share, Owen spent
25 of his share and George spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Julian and Owen have than George in the end?
| |
Julian |
Owen |
George |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
2x6 =
12 u |
$328 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Julian, Owen and George spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 12 u
= 41 u
41 u = 328
1 u = 328 ÷ 41 = 8
Amount that Julian and Owen have in the end
= 8 u + 9 u
= 17 u
Amount that Julian and Owen have more than George in the end
= 17 u - 6 u
= 11 u
= 11 x 8
= $88
Answer(s): $88
