Seth, Julian and Gabriel shared $246. During a shopping trip, Seth spent ³₇ of his share, Julian spent ²₅ of his share and Gabriel spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Seth and Julian have than Gabriel in the end?

	Seth	Julian	Gabriel	Total
Before	7x2 = 14 u	5x3 = 15 u	2x6 = 12 u	$246
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	4x2 = 8 u	3x3 = 9 u	1x6 = 6 u

The amounts that Seth, Julian and Gabriel spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 14 u + 15 u + 12 u
= 41 u

41 u = 246

1 u = 246 ÷ 41 = 6

Amount that Seth and Julian have in the end
= 8 u + 9 u
= 17 u

Amount that Seth and Julian have more than Gabriel in the end
= 17 u - 6 u
= 11 u
= 11 x 6
= $66

Answer(s): $66