Jenson, Reggie and Cody shared $780. During a shopping trip, Jenson spent ²₉ of his share, Reggie spent ³₇ of his share and Cody spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Jenson and Reggie have than Cody in the end?

	Jenson	Reggie	Cody	Total
Before	9x3 = 27 u	7x2 = 14 u	4x6 = 24 u	$780
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	7x3 = 21 u	4x2 = 8 u	3x6 = 18 u

The amounts that Jenson, Reggie and Cody spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u

65 u = 780

1 u = 780 ÷ 65 = 12

Amount that Jenson and Reggie have in the end
= 21 u + 8 u
= 29 u

Amount that Jenson and Reggie have more than Cody in the end
= 29 u - 18 u
= 11 u
= 11 x 12
= $132

Answer(s): $132