Archie, Albert and Valen shared $455. During a shopping trip, Archie spent
29 of his share, Albert spent
37 of his share and Valen spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Archie and Albert have than Valen at first?
|
Archie |
Albert |
Valen |
Total |
Before |
9x3 = 27 u |
7x2 = 14 u |
4x6 = 24 u |
$455 |
Change |
- 2x3 = - 6 u |
- 3x2 = - 6 u |
- 1x6 = - 6 u |
|
After |
7x3 = 21 u |
4x2 = 8 u |
3x6 = 18 u |
|
The amounts that Archie, Albert and Valen spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u
65 u = 455
1 u = 455 ÷ 65 = 7
Amount that Archie and Albert have at first
= 27 u + 14 u
= 41 u
Amount that Archie and Albert have more than Valen at first
= 41 u - 24 u
= 17 u
= 17 x 7
= $119
Answer(s): $119