Zeph, David and Dylan shared $196. During a shopping trip, Zeph spent
27 of his share, David spent
35 of his share and Dylan spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Zeph and David have than Dylan at first?
| |
Zeph |
David |
Dylan |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$196 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Zeph, David and Dylan spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 196
1 u = 196 ÷ 49 = 4
Amount that Zeph and David have at first
= 21 u + 10 u
= 31 u
Amount that Zeph and David have more than Dylan at first
= 31 u - 18 u
= 13 u
= 13 x 4
= $52
Answer(s): $52
