Elijah, Charlie and Zeph shared $550. During a shopping trip, Elijah spent
38 of his share, Charlie spent
25 of his share and Zeph spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Elijah and Charlie have than Zeph in the end?
|
Elijah |
Charlie |
Zeph |
Total |
Before |
8x2 = 16 u |
5x3 = 15 u |
4x6 = 24 u |
$550 |
Change |
- 3x2 = - 6 u |
- 2x3 = - 6 u |
- 1x6 = - 6 u |
|
After |
5x2 = 10 u |
3x3 = 9 u |
3x6 = 18 u |
|
The amounts that Elijah, Charlie and Zeph spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 24 u
= 55 u
55 u = 550
1 u = 550 ÷ 55 = 10
Amount that Elijah and Charlie have in the end
= 10 u + 9 u
= 19 u
Amount that Elijah and Charlie have more than Zeph in the end
= 19 u - 18 u
= 1 u
= 1 x 10
= $10
Answer(s): $10