Brandon, Caden and Julian shared $232. During a shopping trip, Brandon spent ³₄ of his share, Caden spent ²₃ of his share and Julian spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Brandon and Caden have than Julian at first?

	Brandon	Caden	Julian	Total
Before	4x2 = 8 u	3x3 = 9 u	2x6 = 12 u	$232
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	1x2 = 2 u	1x3 = 3 u	1x6 = 6 u

The amounts that Brandon, Caden and Julian spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 8 u + 9 u + 12 u
= 29 u

29 u = 232

1 u = 232 ÷ 29 = 8

Amount that Brandon and Caden have at first
= 8 u + 9 u
= 17 u

Amount that Brandon and Caden have more than Julian at first
= 17 u - 12 u
= 5 u
= 5 x 8
= $40

Answer(s): $40