Wesley, Ryan and Ivan shared $174. During a shopping trip, Wesley spent
34 of his share, Ryan spent
23 of his share and Ivan spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Wesley and Ryan have than Ivan in the end?
| |
Wesley |
Ryan |
Ivan |
Total |
| Before |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
$174 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
1x2 =
2 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Wesley, Ryan and Ivan spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 8 u + 9 u + 12 u
= 29 u
29 u = 174
1 u = 174 ÷ 29 = 6
Amount that Wesley and Ryan have in the end
= 2 u + 3 u
= 5 u
Amount that Wesley and Ryan have more than Ivan in the end
= 5 u - 6 u
= -1 u
= -1 x 6
= $-6
Answer(s): $-6
