Elijah, Dylan and Mark shared $205. During a shopping trip, Elijah spent
37 of his share, Dylan spent
25 of his share and Mark spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Elijah and Dylan have than Mark in the end?
| |
Elijah |
Dylan |
Mark |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
2x6 =
12 u |
$205 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Elijah, Dylan and Mark spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 12 u
= 41 u
41 u = 205
1 u = 205 ÷ 41 = 5
Amount that Elijah and Dylan have in the end
= 8 u + 9 u
= 17 u
Amount that Elijah and Dylan have more than Mark in the end
= 17 u - 6 u
= 11 u
= 11 x 5
= $55
Answer(s): $55
