Seth, Lee and Ivan shared $371. During a shopping trip, Seth spent
37 of his share, Lee spent
25 of his share and Ivan spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Seth and Lee have than Ivan at first?
| |
Seth |
Lee |
Ivan |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$371 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Seth, Lee and Ivan spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 371
1 u = 371 ÷ 53 = 7
Amount that Seth and Lee have at first
= 14 u + 15 u
= 29 u
Amount that Seth and Lee have more than Ivan at first
= 29 u - 24 u
= 5 u
= 5 x 7
= $35
Answer(s): $35
