John, Sean and Tommy shared $372. During a shopping trip, John spent
35 of his share, Sean spent
23 of his share and Tommy spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do John and Sean have than Tommy at first?
| |
John |
Sean |
Tommy |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$372 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that John, Sean and Tommy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 372
1 u = 372 ÷ 31 = 12
Amount that John and Sean have at first
= 10 u + 9 u
= 19 u
Amount that John and Sean have more than Tommy at first
= 19 u - 12 u
= 7 u
= 7 x 12
= $84
Answer(s): $84
