Oscar, Eric and Asher shared $196. During a shopping trip, Oscar spent
27 of his share, Eric spent
35 of his share and Asher spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Oscar and Eric have than Asher at first?
| |
Oscar |
Eric |
Asher |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$196 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Oscar, Eric and Asher spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 196
1 u = 196 ÷ 49 = 4
Amount that Oscar and Eric have at first
= 21 u + 10 u
= 31 u
Amount that Oscar and Eric have more than Asher at first
= 31 u - 18 u
= 13 u
= 13 x 4
= $52
Answer(s): $52
