Ivan, Cody and Henry shared $159. During a shopping trip, Ivan spent
37 of his share, Cody spent
25 of his share and Henry spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Ivan and Cody have than Henry at first?
| |
Ivan |
Cody |
Henry |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$159 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Ivan, Cody and Henry spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 159
1 u = 159 ÷ 53 = 3
Amount that Ivan and Cody have at first
= 14 u + 15 u
= 29 u
Amount that Ivan and Cody have more than Henry at first
= 29 u - 24 u
= 5 u
= 5 x 3
= $15
Answer(s): $15
