Ian, Will and Lee shared $319. During a shopping trip, Ian spent
34 of his share, Will spent
23 of his share and Lee spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Ian and Will have than Lee in the end?
| |
Ian |
Will |
Lee |
Total |
| Before |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
$319 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
1x2 =
2 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Ian, Will and Lee spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 8 u + 9 u + 12 u
= 29 u
29 u = 319
1 u = 319 ÷ 29 = 11
Amount that Ian and Will have in the end
= 2 u + 3 u
= 5 u
Amount that Ian and Will have more than Lee in the end
= 5 u - 6 u
= -1 u
= -1 x 11
= $-11
Answer(s): $-11
