Jeremy, Xavier and George shared $318. During a shopping trip, Jeremy spent ³₇ of his share, Xavier spent ²₅ of his share and George spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Jeremy and Xavier have than George at first?

	Jeremy	Xavier	George	Total
Before	7x2 = 14 u	5x3 = 15 u	4x6 = 24 u	$318
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	4x2 = 8 u	3x3 = 9 u	3x6 = 18 u

The amounts that Jeremy, Xavier and George spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u

53 u = 318

1 u = 318 ÷ 53 = 6

Amount that Jeremy and Xavier have at first
= 14 u + 15 u
= 29 u

Amount that Jeremy and Xavier have more than George at first
= 29 u - 24 u
= 5 u
= 5 x 6
= $30

Answer(s): $30