Ken, Sam and Zane shared $165. During a shopping trip, Ken spent
27 of his share, Sam spent
35 of his share and Zane spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Ken and Sam have than Zane in the end?
| |
Ken |
Sam |
Zane |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
4x6 =
24 u |
$165 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
3x6 =
18 u |
|
The amounts that Ken, Sam and Zane spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 24 u
= 55 u
55 u = 165
1 u = 165 ÷ 55 = 3
Amount that Ken and Sam have in the end
= 15 u + 4 u
= 19 u
Amount that Ken and Sam have more than Zane in the end
= 19 u - 18 u
= 1 u
= 1 x 3
= $3
Answer(s): $3
