Seth, Bryan and Harry shared $186. During a shopping trip, Seth spent
35 of his share, Bryan spent
23 of his share and Harry spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Seth and Bryan have than Harry at first?
| |
Seth |
Bryan |
Harry |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$186 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Seth, Bryan and Harry spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 186
1 u = 186 ÷ 31 = 6
Amount that Seth and Bryan have at first
= 10 u + 9 u
= 19 u
Amount that Seth and Bryan have more than Harry at first
= 19 u - 12 u
= 7 u
= 7 x 6
= $42
Answer(s): $42
