Asher, Sean and Japheth shared $260. During a shopping trip, Asher spent
29 of his share, Sean spent
37 of his share and Japheth spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Asher and Sean have than Japheth at first?
| |
Asher |
Sean |
Japheth |
Total |
| Before |
9x3 =
27 u |
7x2 =
14 u |
4x6 =
24 u |
$260 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
|
The amounts that Asher, Sean and Japheth spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u
65 u = 260
1 u = 260 ÷ 65 = 4
Amount that Asher and Sean have at first
= 27 u + 14 u
= 41 u
Amount that Asher and Sean have more than Japheth at first
= 41 u - 24 u
= 17 u
= 17 x 4
= $68
Answer(s): $68
