Jenson, Peter and Cody shared $246. During a shopping trip, Jenson spent
25 of his share, Peter spent
34 of his share and Cody spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Jenson and Peter have than Cody in the end?
| |
Jenson |
Peter |
Cody |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
3x6 =
18 u |
$246 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
2x6 =
12 u |
|
The amounts that Jenson, Peter and Cody spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 18 u
= 41 u
41 u = 246
1 u = 246 ÷ 41 = 6
Amount that Jenson and Peter have in the end
= 9 u + 2 u
= 11 u
Amount that Jenson and Peter have more than Cody in the end
= 11 u - 12 u
= -1 u
= -1 x 6
= $-6
Answer(s): $-6
