Zane, Ken and Vaidev shared $287. During a shopping trip, Zane spent
25 of his share, Ken spent
34 of his share and Vaidev spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Zane and Ken have than Vaidev in the end?
| |
Zane |
Ken |
Vaidev |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
3x6 =
18 u |
$287 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
2x6 =
12 u |
|
The amounts that Zane, Ken and Vaidev spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 18 u
= 41 u
41 u = 287
1 u = 287 ÷ 41 = 7
Amount that Zane and Ken have in the end
= 9 u + 2 u
= 11 u
Amount that Zane and Ken have more than Vaidev in the end
= 11 u - 12 u
= -1 u
= -1 x 7
= $-7
Answer(s): $-7
