David, Oscar and Tom shared $470. During a shopping trip, David spent
37 of his share, Oscar spent
25 of his share and Tom spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do David and Oscar have than Tom at first?
| |
David |
Oscar |
Tom |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
3x6 =
18 u |
$470 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that David, Oscar and Tom spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u
47 u = 470
1 u = 470 ÷ 47 = 10
Amount that David and Oscar have at first
= 14 u + 15 u
= 29 u
Amount that David and Oscar have more than Tom at first
= 29 u - 18 u
= 11 u
= 11 x 10
= $110
Answer(s): $110
