Glen, Ivan and Sean shared $470. During a shopping trip, Glen spent
37 of his share, Ivan spent
25 of his share and Sean spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Glen and Ivan have than Sean at first?
| |
Glen |
Ivan |
Sean |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
3x6 =
18 u |
$470 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that Glen, Ivan and Sean spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u
47 u = 470
1 u = 470 ÷ 47 = 10
Amount that Glen and Ivan have at first
= 14 u + 15 u
= 29 u
Amount that Glen and Ivan have more than Sean at first
= 29 u - 18 u
= 11 u
= 11 x 10
= $110
Answer(s): $110
