Asher, Julian and John shared $583. During a shopping trip, Asher spent
37 of his share, Julian spent
25 of his share and John spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Asher and Julian have than John at first?
| |
Asher |
Julian |
John |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$583 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Asher, Julian and John spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 583
1 u = 583 ÷ 53 = 11
Amount that Asher and Julian have at first
= 14 u + 15 u
= 29 u
Amount that Asher and Julian have more than John at first
= 29 u - 24 u
= 5 u
= 5 x 11
= $55
Answer(s): $55
