Jenson, Pierre and Jack shared $473. During a shopping trip, Jenson spent ²₇ of his share, Pierre spent ³₅ of his share and Jack spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Jenson and Pierre have than Jack at first?

	Jenson	Pierre	Jack	Total
Before	7x3 = 21 u	5x2 = 10 u	2x6 = 12 u	$473
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	5x3 = 15 u	2x2 = 4 u	1x6 = 6 u

The amounts that Jenson, Pierre and Jack spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 21 u + 10 u + 12 u
= 43 u

43 u = 473

1 u = 473 ÷ 43 = 11

Amount that Jenson and Pierre have at first
= 21 u + 10 u
= 31 u

Amount that Jenson and Pierre have more than Jack at first
= 31 u - 12 u
= 19 u
= 19 x 11
= $209

Answer(s): $209