Zane, Asher and Luke shared $427. During a shopping trip, Zane spent
38 of his share, Asher spent
27 of his share and Luke spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Zane and Asher have than Luke in the end?
| |
Zane |
Asher |
Luke |
Total |
| Before |
8x2 =
16 u |
7x3 =
21 u |
4x6 =
24 u |
$427 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
5x3 =
15 u |
3x6 =
18 u |
|
The amounts that Zane, Asher and Luke spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 427
1 u = 427 ÷ 61 = 7
Amount that Zane and Asher have in the end
= 10 u + 15 u
= 25 u
Amount that Zane and Asher have more than Luke in the end
= 25 u - 18 u
= 7 u
= 7 x 7
= $49
Answer(s): $49
