Simon, Albert and Luis shared $350. During a shopping trip, Simon spent
25 of his share, Albert spent
34 of his share and Luis spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Simon and Albert have than Luis in the end?
| |
Simon |
Albert |
Luis |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$350 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Simon, Albert and Luis spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 350
1 u = 350 ÷ 35 = 10
Amount that Simon and Albert have in the end
= 9 u + 2 u
= 11 u
Amount that Simon and Albert have more than Luis in the end
= 11 u - 6 u
= 5 u
= 5 x 10
= $50
Answer(s): $50
