Carl, Sam and Ian shared $301. During a shopping trip, Carl spent
38 of his share, Sam spent
25 of his share and Ian spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Carl and Sam have than Ian at first?
| |
Carl |
Sam |
Ian |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
2x6 =
12 u |
$301 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Carl, Sam and Ian spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u
43 u = 301
1 u = 301 ÷ 43 = 7
Amount that Carl and Sam have at first
= 16 u + 15 u
= 31 u
Amount that Carl and Sam have more than Ian at first
= 31 u - 12 u
= 19 u
= 19 x 7
= $133
Answer(s): $133
