Jack, Ivan and Fred shared $165. During a shopping trip, Jack spent
27 of his share, Ivan spent
35 of his share and Fred spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Jack and Ivan have than Fred in the end?
| |
Jack |
Ivan |
Fred |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
4x6 =
24 u |
$165 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
3x6 =
18 u |
|
The amounts that Jack, Ivan and Fred spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 24 u
= 55 u
55 u = 165
1 u = 165 ÷ 55 = 3
Amount that Jack and Ivan have in the end
= 15 u + 4 u
= 19 u
Amount that Jack and Ivan have more than Fred in the end
= 19 u - 18 u
= 1 u
= 1 x 3
= $3
Answer(s): $3
