Peter, Oscar and Billy shared $341. During a shopping trip, Peter spent
35 of his share, Oscar spent
23 of his share and Billy spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Peter and Oscar have than Billy at first?
| |
Peter |
Oscar |
Billy |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$341 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Peter, Oscar and Billy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 341
1 u = 341 ÷ 31 = 11
Amount that Peter and Oscar have at first
= 10 u + 9 u
= 19 u
Amount that Peter and Oscar have more than Billy at first
= 19 u - 12 u
= 7 u
= 7 x 11
= $77
Answer(s): $77
