Charlie, Michael and Xavier shared $220. During a shopping trip, Charlie spent ³₈ of his share, Michael spent ²₅ of his share and Xavier spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Charlie and Michael have than Xavier in the end?

	Charlie	Michael	Xavier	Total
Before	8x2 = 16 u	5x3 = 15 u	4x6 = 24 u	$220
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	5x2 = 10 u	3x3 = 9 u	3x6 = 18 u

The amounts that Charlie, Michael and Xavier spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 16 u + 15 u + 24 u
= 55 u

55 u = 220

1 u = 220 ÷ 55 = 4

Amount that Charlie and Michael have in the end
= 10 u + 9 u
= 19 u

Amount that Charlie and Michael have more than Xavier in the end
= 19 u - 18 u
= 1 u
= 1 x 4
= $4

Answer(s): $4