Dylan, Asher and Luke shared $369. During a shopping trip, Dylan spent
25 of his share, Asher spent
34 of his share and Luke spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Dylan and Asher have than Luke at first?
| |
Dylan |
Asher |
Luke |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
3x6 =
18 u |
$369 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
2x6 =
12 u |
|
The amounts that Dylan, Asher and Luke spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 18 u
= 41 u
41 u = 369
1 u = 369 ÷ 41 = 9
Amount that Dylan and Asher have at first
= 15 u + 8 u
= 23 u
Amount that Dylan and Asher have more than Luke at first
= 23 u - 18 u
= 5 u
= 5 x 9
= $45
Answer(s): $45
