Carl, Japheth and Ahmad shared $318. During a shopping trip, Carl spent
37 of his share, Japheth spent
25 of his share and Ahmad spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Carl and Japheth have than Ahmad at first?
| |
Carl |
Japheth |
Ahmad |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$318 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Carl, Japheth and Ahmad spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 318
1 u = 318 ÷ 53 = 6
Amount that Carl and Japheth have at first
= 14 u + 15 u
= 29 u
Amount that Carl and Japheth have more than Ahmad at first
= 29 u - 24 u
= 5 u
= 5 x 6
= $30
Answer(s): $30
