Sean, Jenson and Pierre shared $94. During a shopping trip, Sean spent
37 of his share, Jenson spent
25 of his share and Pierre spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Sean and Jenson have than Pierre in the end?
| |
Sean |
Jenson |
Pierre |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
3x6 =
18 u |
$94 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that Sean, Jenson and Pierre spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u
47 u = 94
1 u = 94 ÷ 47 = 2
Amount that Sean and Jenson have in the end
= 8 u + 9 u
= 17 u
Amount that Sean and Jenson have more than Pierre in the end
= 17 u - 12 u
= 5 u
= 5 x 2
= $10
Answer(s): $10
