Oscar, Albert and Brandon shared $451. During a shopping trip, Oscar spent ²₅ of his share, Albert spent ³₄ of his share and Brandon spent ¹₃ of his share. Given that all three boys each spent the same amount of money, how much more money do Oscar and Albert have than Brandon in the end?

	Oscar	Albert	Brandon	Total
Before	5x3 = 15 u	4x2 = 8 u	3x6 = 18 u	$451
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	3x3 = 9 u	1x2 = 2 u	2x6 = 12 u

The amounts that Oscar, Albert and Brandon spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 15 u + 8 u + 18 u
= 41 u

41 u = 451

1 u = 451 ÷ 41 = 11

Amount that Oscar and Albert have in the end
= 9 u + 2 u
= 11 u

Amount that Oscar and Albert have more than Brandon in the end
= 11 u - 12 u
= -1 u
= -1 x 11
= $-11

Answer(s): $-11