Luke, Warren and Billy shared $62. During a shopping trip, Luke spent
35 of his share, Warren spent
23 of his share and Billy spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Luke and Warren have than Billy at first?
| |
Luke |
Warren |
Billy |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$62 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Luke, Warren and Billy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 62
1 u = 62 ÷ 31 = 2
Amount that Luke and Warren have at first
= 10 u + 9 u
= 19 u
Amount that Luke and Warren have more than Billy at first
= 19 u - 12 u
= 7 u
= 7 x 2
= $14
Answer(s): $14
