Sean, Ken and Elijah shared $605. During a shopping trip, Sean spent
38 of his share, Ken spent
25 of his share and Elijah spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Sean and Ken have than Elijah in the end?
| |
Sean |
Ken |
Elijah |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
4x6 =
24 u |
$605 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Sean, Ken and Elijah spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 24 u
= 55 u
55 u = 605
1 u = 605 ÷ 55 = 11
Amount that Sean and Ken have in the end
= 10 u + 9 u
= 19 u
Amount that Sean and Ken have more than Elijah in the end
= 19 u - 18 u
= 1 u
= 1 x 11
= $11
Answer(s): $11
