Luis, Caden and Sean shared $106. During a shopping trip, Luis spent
37 of his share, Caden spent
25 of his share and Sean spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Luis and Caden have than Sean at first?
| |
Luis |
Caden |
Sean |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$106 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Luis, Caden and Sean spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 106
1 u = 106 ÷ 53 = 2
Amount that Luis and Caden have at first
= 14 u + 15 u
= 29 u
Amount that Luis and Caden have more than Sean at first
= 29 u - 24 u
= 5 u
= 5 x 2
= $10
Answer(s): $10
