Ivan, Oscar and Zane shared $105. During a shopping trip, Ivan spent
25 of his share, Oscar spent
34 of his share and Zane spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Ivan and Oscar have than Zane at first?
| |
Ivan |
Oscar |
Zane |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$105 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Ivan, Oscar and Zane spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 105
1 u = 105 ÷ 35 = 3
Amount that Ivan and Oscar have at first
= 15 u + 8 u
= 23 u
Amount that Ivan and Oscar have more than Zane at first
= 23 u - 12 u
= 11 u
= 11 x 3
= $33
Answer(s): $33
