Peter, Julian and Glen shared $441. During a shopping trip, Peter spent
38 of his share, Julian spent
25 of his share and Glen spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Peter and Julian have than Glen in the end?
| |
Peter |
Julian |
Glen |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
3x6 =
18 u |
$441 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that Peter, Julian and Glen spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 18 u
= 49 u
49 u = 441
1 u = 441 ÷ 49 = 9
Amount that Peter and Julian have in the end
= 10 u + 9 u
= 19 u
Amount that Peter and Julian have more than Glen in the end
= 19 u - 12 u
= 7 u
= 7 x 9
= $63
Answer(s): $63
